15C^2+22C-48=0

Solution for 15C^2+22C-48=0 equation:

Simplifying
15C2 + 22C + -48 = 0

Reorder the terms:
-48 + 22C + 15C2 = 0

Solving
-48 + 22C + 15C2 = 0

Solving for variable 'C'.

Factor a trinomial.
(-8 + -3C)(6 + -5C) = 0

Subproblem 1
Set the factor '(-8 + -3C)' equal to zero and attempt to solve:

Simplifying
-8 + -3C = 0

Solving
-8 + -3C = 0

Move all terms containing C to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + -3C = 0 + 8

Combine like terms: -8 + 8 = 0
0 + -3C = 0 + 8
-3C = 0 + 8

Combine like terms: 0 + 8 = 8
-3C = 8

Divide each side by '-3'.
C = -2.666666667

Simplifying
C = -2.666666667
Subproblem 2
Set the factor '(6 + -5C)' equal to zero and attempt to solve:

Simplifying
6 + -5C = 0

Solving
6 + -5C = 0

Move all terms containing C to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -5C = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -5C = 0 + -6
-5C = 0 + -6

Combine like terms: 0 + -6 = -6
-5C = -6

Divide each side by '-5'.
C = 1.2

Simplifying
C = 1.2
Solution
C = {-2.666666667, 1.2}